SOLUTION: Solve the equation by extracting the square roots. List both the exact solution and its approximation rounded to two decimal places. sqrt4Xsq = sqrt36

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve the equation by extracting the square roots. List both the exact solution and its approximation rounded to two decimal places. sqrt4Xsq = sqrt36      Log On


   

Question 1175285: Solve the equation by extracting the square roots. List both the exact solution and its approximation rounded to two decimal places.
sqrt4Xsq = sqrt36
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
IF
sqrt%28%284x%29%5E2%29+=+sqrt%2836%29
          4x = ± 6
           x = 6/4  = 3/2  
           x= -6/4  = -3/2
       
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