SOLUTION: <img src="http://img528.imageshack.us/img528/6756/mathyg6.png"> <h1><big>PLEASE HELP! :]

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: <img src="http://img528.imageshack.us/img528/6756/mathyg6.png"> <h1><big>PLEASE HELP! :]      Log On


   



Question 117520:

PLEASE HELP! :]
Answer by BrittanyM(80) About Me  (Show Source):
You can put this solution on YOUR website!
I couldn't help but be drawn to your question! :)

For problem a, we need to assess the definition of a derivative. That is, the slope of a function at any given point. So, in a standard function, the slope at the turning points will be zero, thus, we have a zero for the representation of this point on our differentiated gragh.

And as for b, let's graph the original function:

graph%28+600%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E3%29

Where the derivative is zero, the graph is not at a turning point.

If you need any further clarification, or just have anymore math problems, feel free to e-mail me directly at brittany@flatearthfilms.net.