Question 1175198: 1. Arlene and Lito are travelling north in separate cars on the same highway. Arlene is travelling at 65kph and Lito at 75kph. Arlene passes Dau exit at 2:30 PM and Lito passes the same exit at 2:45PM. At what time will lito catch up to Arlene?
2. A car travelling at an average speed of 55 kilometer per hour leaves town A for town B, a distance of 120 kilometers. At the same time, another car, travelling on the same highway at an average speed of 45kilometer per hour leaves town B for town A. In how many hours will they meet? How far from town A will they meet?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! Lito is 15 minutes behind or 16.25 km behind Arlene when he reaches the exit.
He is gaining at 10 km/h
It will take him 1.625 hours or 1h37.5 min and the time would be 4:22.30
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or
Arlene is 16.25 km past the exit and her distance before being caught in x hours is 16.25+65x km
In x hours Lito will have gone 75 x km
Those two are equal
so 10x=16.25 km
x=1.625 hours as above.
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They meet when their total distance is 120 km. That will take x hours
One car will go 55x km and the other 45x km in that time
so 100x=120
x=1.2 hours
the faster car will have gone 66 km from A
the slower car will have gone 54 km from B
66 km is the answer
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