Question 1175182: Vannessa plans to arrange A,B,C,D,E,F,G and H in a row on the wall. Find the number of Permutations for the following:
A and B must be places next to each other
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
A and B must be places next to each other: Consider them as one unit
Find the number of Permutations: 7!(2) (AB 0r BA))
Wish You the Best in your Studies.
Answer by ikleyn(52803)  (Show Source):
You can put this solution on YOUR website! .
For the rest of 6 letters, C, D, E, F, G and H, there are 6! = 720 possible permutations.
For each of these 720 permutations, we have 7 positions to place the blocked AB or BA.
THEREFORE, the full number of possible arrangements, satisfying the posed conditions, is
6!*2*7 = 2*7! = 10080. ANSWER
Solved.
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