SOLUTION: Tacoma's population in 2000 was about 200 thousand, and has been growing by 9% every year. If this continues, what will Tacoma's population be in 2011?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Tacoma's population in 2000 was about 200 thousand, and has been growing by 9% every year. If this continues, what will Tacoma's population be in 2011?      Log On


   



Question 1175156: Tacoma's population in 2000 was about 200 thousand, and has been growing by 9% every year. If this continues, what will Tacoma's population be in 2011?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Growing at 9% = 0.09 per year means an annual growth factor of 1+0.09 = 1.09.

The growth factor over a period of 11 years will be (1.09)^11.

The projected population in 2011 will be

200000%281.09%29%5E11+=+516085