If we know that , then this also means that because
csc is shorthand for "cosecant"
Because , and , this makes y > 0 and it places our angle somewhere in quadrant I or quadrant II. This is where the terminal point has a positive y coordinate. It's somewhere above the x axis.
Furthermore, if and , then x > 0 tells us we're somewhere to the right of the y axis where x is positive.
So with x > 0 and y > 0, we know that the terminal point (x,y) is somewhere in quadrant I. This is the northeast quadrant, ie the upper-right quadrant.