You can put this solution on YOUR website! Decompose into a partial fraction
:
:
Numerator degree is greater than the denominator:
Divide using long division:
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(x^2-2x-3)|2x^3 + x^2 - 3x+ 5
:
You should get 2x + 5: + Remainder
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Decompose the remainder:
Factor the denominator = + =
:
Since these fractions have the same denominator, their numerators have to be equal
13x+20 = A(x+1) + B(x-3)
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Let x = 3, then B drops out and we can solve for A:
13(3) + 20 = A(3+1) + B(3-3)
:
39 + 20= A(4) + B(0)
:
59 = 4A
:
A = 59/4
:
A = 14.75
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Let x = -1, then A drops out
13(-1) + 20 = A(-1+1) + B(-1-3)
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-13 + 20 = A(0) + B(-4)
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7 = -4B
:
B = 7/-4
:
B = -1.75
:
The quotient and the partial fractions:
(2x + 5) + +
