SOLUTION: A jazz concert brought $137,000 on the sale of 8,800 tickets. If the tickets sold for $10 and $20 each, how many of each type were sold?

Algebra ->  Linear-equations -> SOLUTION: A jazz concert brought $137,000 on the sale of 8,800 tickets. If the tickets sold for $10 and $20 each, how many of each type were sold?       Log On


   

Question 1174771: A jazz concert brought $137,000 on the sale of 8,800 tickets. If the tickets sold for $10 and $20 each, how many of each type were sold?
Answer by VFBundy(438) About Me  (Show Source):
You can put this solution on YOUR website!
x = # of $10 tickets
y = # of $20 tickets

x + y = 8800
10x + 20y = 137000

Multiply first equation by -20:

-20(x + y) = -20(8800)

-20x - 20y = -176000

Here are your two equations:

-20x - 20y = -176000
10x + 20y = 137000

Add the two equations together:

-10x = -39000

Solve for x:

x = 3900

Plug in x = 3900 into the original first equation:

x + y = 8800

3900 + y = 8800

Solve for y:

y = 4900

x = # of $10 tickets = 3900
y = # of $20 tickets = 4900