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| Question 1174769:  Homer and Mike were replacing the boards on Mike's old deck. Mike can do the job alone in 1 hour less time than Homer. They worked together for 5 hours until Homer had to go home. Mike finished the job working by himself in an additional 2 hours. How long would it have taken Homer to fix the deck himself?
 Answer by VFBundy(438)
      (Show Source): 
You can put this solution on YOUR website! Homer's rate of work =  of the job per hour Mike's rate of work =
  of the job per hour 
 Rate of work working together =
  +  of the job per hour 
 Simplify:
 
 
  +  
 
  
 
  
 Rate of work working together =
  of the job per hour 
 After working five hours together, calculate the amount of the job that was completed:
 
 
  
 
  
 Therefore, the amount of the job that is left to be completed is:
 
 
  
 
  
 
  
 
  
 
  
 
  
 Mike finishes the job in two hours.  This means Mike's rate of work per hour is:
 
 
  *  
 
  
 So, Mike's rate of work is
  of the job per hour. 
 From earlier, we know that Mike's rate of work is also
  of the job per hour.  Therefore: 
 
  =  
 Solve for x.
 
 Cross-multiply:
 
 
  =  
 
  =  
 
  =  
 Use the quadratic formula to solve for x:
 
 x =
  = 0.40 x =
  = 12.60 
 There are two solutions.  Because Mike's rate of work is
  of the job per hour, the first solution, x = 0.40, would make Mike's rate of work  .  Since this is a negative rate of work, this is impossible. 
 Therefore, we are left with x = 12.60
 
 We are looking how long it would have taken Homer to fix the deck working alone.  Homer's rate of work is
  of the job per hour.  Plugging in x = 12.60, this means Homer's rate of work is  of the job per hour.  This means it would have taken Homer 12.60 hours to fix the deck working alone.
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