SOLUTION: For a positive integer n, the complex number
zk = n r cos 𝜃 + 2𝜋k n + i sin 𝜃 + 2𝜋k n
where k = 0, 1, 2, . . . , n − 1.
Consider the following.
Cube roots of
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-> SOLUTION: For a positive integer n, the complex number
zk = n r cos 𝜃 + 2𝜋k n + i sin 𝜃 + 2𝜋k n
where k = 0, 1, 2, . . . , n − 1.
Consider the following.
Cube roots of
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Question 1174593: For a positive integer n, the complex number
zk = n r cos 𝜃 + 2𝜋k n + i sin 𝜃 + 2𝜋k n
where k = 0, 1, 2, . . . , n − 1.
Consider the following.
Cube roots of 2744
(a) Use the theorem above to find the indicated roots of the complex number. (Enter your answers in trigonometric form.)
z0=
z1=
z2=
(b) Write each of the roots in standard form.
z0=
z1=
z2=
