SOLUTION: I am afraid I am doing the following problem wrong. Please help The problme is......find the equation for the folowing lines and then graph them using any graphing utility. (

Algebra ->  Graphs -> SOLUTION: I am afraid I am doing the following problem wrong. Please help The problme is......find the equation for the folowing lines and then graph them using any graphing utility. (      Log On


   

Question 117454: I am afraid I am doing the following problem wrong. Please help
The problme is......find the equation for the folowing lines and then graph them using any graphing utility.
(A) Perpendicular to x+2y=10, and passing through the point (1,1)
I thought I was supposed to first solve for x and y which I got y=5 and x=10.....WHen I graph that i get a straight line passing throu (1,1).
Can you please help? THank you!!!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First, you have to find the slope of your first line, x+2y=10.
You need to go to slope-intercept form.
x%2B2y=10
2y=-x%2B10
y=-%281%2F2%29x%2B5

Now you know the slope of your first line is -1/2.
Then use the point slope form of a line to get the equation of the second line.
Perpendicular lines have slopes that have a particular relationship.
That is, their slopes are negative reciprocals.
m%5B2%5D=-1%2Fm%5B1%5D
The slope of your second line is then,
m%5B2%5D=-1%2F%28-1%2F2%29
m%5B2%5D=2
Now use the point-slope form and substitute,
y-y%5B1%5D=m%28x-x%5B1%5D%29
where
x%5B1%5D=1 and y%5B1%5D=1
y-1=2%28x-1%29
y-1=2x-2
highlight%28y=2x-1%29