SOLUTION: hey, I need ASAP help with this if you could please answer each part detailed and clear that would be very helpful! thankyou:) A hydro pole is supported by a 20m guy wire that

Algebra ->  Trigonometry-basics -> SOLUTION: hey, I need ASAP help with this if you could please answer each part detailed and clear that would be very helpful! thankyou:) A hydro pole is supported by a 20m guy wire that       Log On


   

Question 1174478: hey, I need ASAP help with this if you could please answer each part detailed and clear that would be very helpful! thankyou:)
A hydro pole is supported by a 20m guy wire
that makes an angle of 48° with the level ground. A 16m guy wire is to be fastened to the other
side of the pole for reinforcement. Both wires are attached to the pole at the top.
a. What angle should the second wire make with the ground? Round your answer to the
nearest degree.
b. How tall is the hydro pole? Round your answer to the nearest tenth of a metre.
c. How far is the base of the 20m guy wire from the base of the 16m guy wire? Round your
answer to the nearest tenth of a metre.
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
label your triangle ABCD.
A is the foot of the bottom of the 16 foot wire.
B is the top of the pole
C is the foot of the bottom of the 20 foot wire.
D is the base of the pole.

the height of the pole is BD.
the angle that the second wire makes with the ground is angle BAD.
the angle that the first wire makes with the ground is angle BCD.
the distance between the bottom of the 20 meter wire and the bottom of the 16 meter wire is AC. AC is the sum of AD and DC.
the length of BC is given as 20 meters.
the length of AB is given as 16 meters.

to find the height of the pole, use sin(48) = BD / 20
solve for BD to get BD = 20 * sin(48) = 14.86289651 meters.

to find the angle that the 16 meter pole makes with the ground, use angle BAD = arcsin(BD/16) = arcsin(14.86289651/16) = 68.26879086 degrees.

to find the length of AD, use 16^2 - BD^2 = 16^2 - 14.86289651^2 = AD^2 and then take the square root of that to find AD = 5.924044847.

to find the length of DC, use 20^2 - BD^2 = 20^2 - 14.86289651^2 = DC^2 and then take the square root of that to find DC = 13.38261213.

those are your answers.

here's a picture to help you see where everything fits.

your solutions are in the picture rounded to 1 d3ecimal place.



i'll be available to answer any questions you night have regarding this.

theo