SOLUTION: A town's population has been growing linearly. In 2003 the population was 68,000. The population has been growing by 2200 people each year. Write an equation for the population,

Algebra ->  Linear-equations -> SOLUTION: A town's population has been growing linearly. In 2003 the population was 68,000. The population has been growing by 2200 people each year. Write an equation for the population,      Log On


   



Question 1174385: A town's population has been growing linearly. In 2003 the population was 68,000. The population has been growing by 2200 people each year.
Write an equation for the population, P, x years after 2003.
Use the formula to find the population in 2009:

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

A town's population has been growing linearly. In 2003 the population was 68,000. The population has been growing by 2200 people each year.
Write an equation for the population, P, x years after 2003.
Use the formula to find the population in 2009:
Rate of change/Slope: 2,200
y-intercept, with INITIAL year being 0, (0, 68,000)
Equation of a LINE: y = mx + b
Equation for the population, x years after INITIAL year/2003: highlight_green%28matrix%281%2C3%2C+y%2C+%22=%22%2C+%222%2C200%22x+%2B+%2268%2C000%22%29%29
Substitute 6 (2009 - 2003) for x to find population in 2009.