Question 1174374: Scott and Laura have both invested some money. Scott invested $2,500 more than Laura and at a 2% higher interest rate. If Scott received $900 annual interest and Laura received $400, how much did Scott invest? (There are two possibilities for how much Scott invested.
Found 2 solutions by greenestamps, ikleyn: Answer by greenestamps(13216) (Show Source): Answer by ikleyn(52915) (Show Source):
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Scott and Laura have both invested some money. Scott invested $2,500 more than Laura and at a 2% higher interest rate.
If Scott received $900 annual interest and Laura received $400, how much did Scott invest?
(There are two possibilities for how much Scott invested.
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This problem has very interesting, elegant and unexpected solution.
In addition, it has beautiful core, that you rarely may find in such problems.
It is WORTH to learn. It is WORTH to teach. Watch my steps attentively.
Let x be the the annual interest of the Scott's investment (as decimal).
Then Laura's annual interest is (x-0.02).
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| This variable x is the only unknown I will use in my solution. |
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Then the Scott's principal investment is {{900/x}}} dollars,
while the Laura's principal investment is dollars.
According to the condition, the difference of their principals is 2500;
it gives you the core equation
- = 2500. (1)
At this point, the setup is just completed, and now I start solving this equation.
First, divide by 100 both sides
- = 25.
Next, multiply both sides by x*(x-0.02) and simplify, step by step
9*(x-0.02) - 4x = 25x*(x-0.02)
9x - 0.18 - 4x = 25x^2 - 0.5x
5x -0.18 = 25x^2 - 0.5x
25x^2 - 5.5x + 0.18 = 0
= = = .
So, there are two roots: = = = 0.18,
and = = = 0.04.
Both the roots satisfy the basic equation (1):
x= 0.18: - = 5000 - 2500 = 2500 dollars. ! correct !
and
x= 0.14: - = 22500 - 20000 = 2500 dollars. ! correct !
Thus for Scott's investment, we have two possible answers: a) = 5000 dollars and/or b) = 22500 dollars.
Solved.
Honestly, it is for the first time in my life I see so beatiful solution to this class of problems.
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