SOLUTION: A telephone company offers two long-distance plans. Plan A: $25 per month and .05 cents per minute Plan B: $5 per month and .12 cents per minute For how many minutes of long

Algebra ->  Inequalities -> SOLUTION: A telephone company offers two long-distance plans. Plan A: $25 per month and .05 cents per minute Plan B: $5 per month and .12 cents per minute For how many minutes of long       Log On


   

Question 1174353: A telephone company offers two long-distance plans.
Plan A: $25 per month and .05 cents per minute
Plan B: $5 per month and .12 cents per minute
For how many minutes of long distance calls would Plan B be financially advantageous?
Found 2 solutions by ikleyn, ewatrrr:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

     Plan A       Plan B

    25 + 0.05x > 5 + 0.12x


Solve this inequality


    25 - 5     > 0.12x - 0.05x


       20      >      0.07x


       x       <       20%2F0.07 = 285.7  minutes.


If you want to round to integer minutes,  then the ANSWER is


        Plan B is cheaper for  less than or equal to 285 minutes.


It becomes more expensive starting from 286 integer minutes.



Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
A = $25 + .05m
B = $5 + .12m
Checking out when they would cost the same.
 5 + .12m = $25 + .05m
        .07m = 20
           m  = 286m  rounded up to whole number 

minutes of long distance calls < 286m Plan B would be financially advantageous
     Wish You the Best in your Studies.