SOLUTION: For the system of equations : x+2y+3z=73 3x+y+z=49 2x+3y+4z=106 In matrix form AX=B,the inverse matrix A^-1 is A^-1 = 1/2 [ 1 1 -1

Algebra ->  Matrices-and-determiminant -> SOLUTION: For the system of equations : x+2y+3z=73 3x+y+z=49 2x+3y+4z=106 In matrix form AX=B,the inverse matrix A^-1 is A^-1 = 1/2 [ 1 1 -1       Log On


   

Question 1174243: For the system of equations :
x+2y+3z=73
3x+y+z=49
2x+3y+4z=106
In matrix form AX=B,the inverse matrix A^-1 is A^-1 = 1/2 [ 1 1 -1
-10 -2 8
7 1 -5 ]
Use A^-1 to solve the system. Show all work.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi



A=+%28matrix%283%2C3%2C1%2C2%2C3%2C3%2C1%2C1%2C2%2C3%2C4%29%29



A%5E%28-1%29+=+%281%2F2%29%28matrix%283%2C3%2C1%2C1%2C-1%2C-10%2C-2%2C8%2C7%2C1%2C-5%29%29


  %28matrix%283%2C3%2C1%2C1%2C-1%2C-10%2C-2%2C8%2C7%2C1%2C-5%29%29 *%28matrix%283%2C1%2C73%2C49%2C106%29%29 =%28matrix%283%2C1%2C16%2C20%2C30%29%29

Note:
   (1)73 + (1)49 + (-1) 106 = 16
  -730  - 98 + (8)106 = 20  
   (7)73 + 49 + (-5)106= 30


 (1/2)%28matrix%283%2C1%2C16%2C20%2C30%29%29  = %28matrix%283%2C1%2C8%2C10%2C15%29%29

   (8,10,15)  the solution for this system of Equations


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