SOLUTION: 4. The distance a body falls from rest (neglecting air resistance) varies directly as the square of the time it falls. If an object drops 64 feet in 2 seconds, how many seconds wil
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Question 1174184: 4. The distance a body falls from rest (neglecting air resistance) varies directly as the square of the time it falls. If an object drops 64 feet in 2 seconds, how many seconds will it take an object to reach the sea if it is dropped from a plane 2500 feet above the sea level? (show complete solution thanks!) Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! 4. The distance a body falls from rest (neglecting air resistance) varies directly as the square of the time it falls.
d = kt^2 where
d = distance after t time
t = time
k = constant
If an object drops 64 feet in 2 seconds,
Find k
k*2^2 = 64
k = 64/4
k = 16
the equation now d = 16t^2
how many seconds will it take an object to reach the sea if it is dropped from a plane 2500 feet above the sea level? (show complete solution thanks!)
16t^2 = 2500
t^2 = 2500/16
t^2 = 156.25
t =
t = 12.5 seconds
