SOLUTION: In how many ways can a committee of 8 students from 12 males and 10 females if there must be 5 males in the committee?

Algebra ->  Permutations -> SOLUTION: In how many ways can a committee of 8 students from 12 males and 10 females if there must be 5 males in the committee?       Log On


   



Question 1174182: In how many ways can a committee of 8 students from 12 males and 10 females if there must be 5 males in the committee?
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

12 males and 10 females, in all.


 5 males and  3 females in the committee . . . 


    C%5B12%5D%5E5.C%5B10%5D%5E3 = %2812%2A11%2A10%2A9%2A8%29%2F%281%2A2%2A3%2A4%2A5%29.%2810%2A9%2A8%29%2F%281%2A2%2A3%29 = 792*120 = 95040 ways.

Solved, answered, explained and completed.