SOLUTION: Find the area of a triangle bounded by the y-axis, the line
f(x) = 7− (2)/(7)x
and the line perpendicular to f(x) that passes through the origin. (Round your answer to two dec
Question 1174149: Find the area of a triangle bounded by the y-axis, the line
f(x) = 7− (2)/(7)x
and the line perpendicular to f(x) that passes through the origin. (Round your answer to two decimal places.) Found 3 solutions by greenestamps, ewatrrr, ikleyn:Answer by greenestamps(13200) (Show Source):
Hi,
Find the area of a triangle bounded by the y-axis, the line f(x) = 7− (2)/(7)x
y = -(2/7)x + 7
and the line perpendicular to f(x) that passes through the origin...
y = (7/2)x
----------
7 − (2/7)x = (7/2)x
7 = (4 + 49)/14)x = (x)53/14
(14/53)7 = x = 1.849 and y = 6.47
-------------
D =
P(1.849, 6.47) & P(0,0) and P(1.849, 6.47) & P(0,7)
Area = (1/2)bh =
Will leave it to You to finish up. Important You are comfortable with Your calculator.
Wish You the Best in your Studies.
It is because she selected IMPROPER way to solve the problem.
Actually, there is MUCH SIMPLER way, pointed by @greenestamps.
I decided to complete the solution in that way to convince you HOW SIMPLE it is.
The two lines are
y = + 7
y = .
Their intersection is
= .
Multiply both sides by 14 to get
-4x + 98 = 49x
98 = 49x + 4x = 53x
x = .
You may consider the segment [0,7] along the y-axis as the base of our right-angled triangle.
Thus the base has the length of 7 units, while the altitude of the triangle, drawn to this base is units long.
Hence, the area of the triangle is = = 6.472 square units (rounded). ANSWER
Solved.
May the Lord saves you from solving the problem in a way how @ewatrrr does it . . .
Let her post be a lesson for you on how this problem SHOULD NOT be solved.