SOLUTION: find 3 consecutive integers such that 4 times the middle integer plus the largest integer is 9 less than 6 times the smallest.

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Question 117411This question is from textbook Holt Algebra 1
: find 3 consecutive integers such that 4 times the middle integer plus the largest integer is 9 less than 6 times the smallest. This question is from textbook Holt Algebra 1

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The integers are n,n%2B1,n%2B2
4%28n%2B1%29+%2B+%28n%2B2%29+=+6n+-+9
4n+%2B+4+%2B+n+%2B+2++=+6n+-+9
5n+%2B+6+=+6n+-+9
n+=+15
The integers are 15,16,17
check answers
4%28n%2B1%29+%2B+%28n%2B2%29+=+6n+-+9
4%2A16+%2B+17+=+6%2A15+-+9
64+%2B+17+=+90+-+9
81+=+81
OK