SOLUTION: Kate wants to choose 3 out 13 different items as the Christmas presents. Given that 4 items are from shop B, and 3 items are from shop C, find the number of combinations in each o

Algebra ->  Permutations -> SOLUTION: Kate wants to choose 3 out 13 different items as the Christmas presents. Given that 4 items are from shop B, and 3 items are from shop C, find the number of combinations in each o      Log On


   



Question 1173926: Kate wants to choose 3 out 13 different items as the Christmas presents. Given that 4 items are from
shop B, and 3 items are from shop C, find the number of combinations in each of the following cases,
Choosing 3 items from the same shop.
can you help me with this thank you so much :)

Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
6 A 4 B, 3 C 13 different items
Choosing 3 items from the same shop:
find the number of combinations
(6C3)+ (4C3) + (3C3)
Wish You the Best in your Studies.

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
Kate wants to choose 3 out 13 different items as the Christmas presents. Given that 4 items are from
shop B, and 3 items are from shop C, find the number of combinations in each of the following cases,
Choosing 3 items from the same shop.
can you help me with this thank you so much :)
~~~~~~~~~~~~~~~~~


        Formulation of this problem is  LAME.



It is  LAME,  because it  DOES  NOT  SAY  that the rest of items,  13 - 4 - 3 = 6  are from the shop  A.

Moreover,  the shop  A  is not mentioned in the problem,  at all.


            Hey,  are you  OK  there,  at the opposite side of the  Internet,  formulating your tasks in this curved way ?



NEVER  SAW  such  LAME  formulation . . .


Who created it ?   Who is the author ?


In such form,  your creations are good only for re-cycling . . .



            The same relates to the solution by @ewatrrr . . .


...............

In my understanding,  when the tutor sees such a post,  there is only one right way to treat it:

                    to return it to the visitor for correction.


                        Any other action is WRONG.