SOLUTION: a rectangle has a perimeter of 26. The length is -w^4+6. write and simp-lified expression for the width of the rectangle?

Algebra ->  Pythagorean-theorem -> SOLUTION: a rectangle has a perimeter of 26. The length is -w^4+6. write and simp-lified expression for the width of the rectangle?      Log On


   

Question 1173882: a rectangle has a perimeter of 26. The length is -w^4+6. write and simp-lified expression for the width of the rectangle?
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The perimeter is twice the length plus twice the width.

P = 2L + 2W

26 = 2(-w^4+6)+2W

Solve for W.

Note that "w" and "W" are not the same....

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Using exactly what you describe and ASSUMING w is for width,
2%28-w%5E4%2B6%29%2B2w=26
-
2w-2w%5E4%2B12=26
w-w%5E4=13-6
w-w%5E4=7
I believe not.
Recheck your problem description.