SOLUTION: The point P(x, y) is on the unit circle in Quadrant IV. If x = sqrt(39)/8, find y.

Algebra ->  Trigonometry-basics -> SOLUTION: The point P(x, y) is on the unit circle in Quadrant IV. If x = sqrt(39)/8, find y.      Log On


   

Question 1173813: The point P(x, y) is on the unit circle in Quadrant IV.
If x = sqrt(39)/8, find y.
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Instead of doing your problem for you, I'll do one exactly like it,
step-by-step that you can use as a model to go by:

The point P(x, y) is on the unit circle in Quadrant IV.
If x = sqrt(65)/9, find y.

x%5E2%22%22%2B%22%22y%5E2%22%22=%22%221
%28sqrt%2865%29%2F9%29%5E2%22%22%2B%22%22y%5E2%22%22=%22%221
65%2F81%22%22%2B%22%22y%5E2%22%22=%22%221
65%22%22%2B%22%2281y%5E2%22%22=%22%2281
81y%5E2%22%22=%22%2281%22%22-%22%2265
81y%5E2%22%22=%22%2216
y%5E2%22%22=%22%2216%2F81
y%22%22=%22%22%22%22+%2B-+sqrt%2816%2F81%29
y%22%22=%22%22%22%22+%2B-+sqrt%2816%29%2Fsqrt%2881%29
y%22%22=%22%22%22%22+%2B-+4%2F9

Since all points in Quadrant IV are (+,-), the 
y-coordinate is -4%2F9

Now do yours the exact same way.

Edwin