SOLUTION: What is the remainder when the polynomial g(x) = x^3-14x^2+18x+72 is divided by x-1? I got (77)/(x-1). Is that correct? If not, can you tell me what I did wrong? Thank you!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: What is the remainder when the polynomial g(x) = x^3-14x^2+18x+72 is divided by x-1? I got (77)/(x-1). Is that correct? If not, can you tell me what I did wrong? Thank you!      Log On


   

Question 1173720: What is the remainder when the polynomial
g(x) = x^3-14x^2+18x+72
is divided by x-1?
I got (77)/(x-1). Is that correct? If not, can you tell me what I did wrong? Thank you!
Found 2 solutions by greenestamps, ewatrrr:
Answer by greenestamps(13214) About Me  (Show Source):
You can put this solution on YOUR website!


The remainder when a polynomial p(x) is divided by the linear polynomial x-a is the polynomial evaluated at a, p(a).

In this example, p(1) = 1 -14 +18 +72 = 77.

So "77/(x-1)" COULD be considered the remainder; but in most contexts the remainder would be just "77".

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

g(x) = x^3-14x^2+18x+72 is divided by x-1?

What is the remainder

(77)/(x-1)  Yes, Good Work.

Wish You the Best in your Studies.

1 |	1	-14	18	72

		  1    -13	 5

	1	-13	  5	77