SOLUTION: u = −10i − 5j v = −6i + 3j Find the degree measure of the angle 𝜃 between the vectors. (Round your answer to two decimal places.) 𝜃 = _____°

Algebra ->  Trigonometry-basics -> SOLUTION: u = −10i − 5j v = −6i + 3j Find the degree measure of the angle 𝜃 between the vectors. (Round your answer to two decimal places.) 𝜃 = _____°      Log On


   



Question 1173622: u = −10i − 5j
v = −6i + 3j
Find the degree measure of the angle 𝜃 between the vectors. (Round your answer to two decimal places.)
𝜃 = _____°

Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

The dot product of two vectors is defined as
u·v = |u||v|cos(θ)

and the dot product also happens to be the sum of products of corresponding components:
u·v = u%5Bx%5Dv%5Bx%5D+%2B+u%5By%5Dv%5By%5D
So we have all that is needed to solve for θ:

|u| = +sqrt%28%28-10%29%5E2+%2B+%28-5%29%5E2%29+ = +sqrt%28125%29+ = +5sqrt%285%29+
|v| = +sqrt%28%28-6%29%5E2+%2B+3%5E2%29+ = +sqrt%2845%29+ = +3sqrt%285%29+
and
+u%5Bx%5Dv%5Bx%5D+%2B+u%5By%5Dv%5By%5D = +%28-10%29%28-6%29+%2B+%28-5%29%283%29+ = +45+

Putting it all together:
5sqrt%285%29%2A3sqrt%285%29%2Acos%28theta%29+ = 45+
75+cos%28theta%29+ = 45+
cos(θ) = 45%2F75+
θ = cos%5E-1%2845%2F75%29+ = highlight%28+53.13%5Eo+%29+