Question 1173614: how many outcomes are possible for a car with 2 models, 8 colors, and any combination of 4 options?
Found 4 solutions by ewatrrr, ikleyn, mccravyedwin, greenestamps:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi,
Model I has 8 colors & 4 options, Model II has 8 colors & 4 options
Model I outcomes possible:
8(4C4 + 4C3 + 4C2 + 4C1 ) = 8(1 + 4 + 6 + 4) = 8(15)
Same number of Outcomes for Model II
Total outcomes: 2(8)(15)
Wish You the Best in your Studies.
Answer by ikleyn(52864)  (Show Source):
You can put this solution on YOUR website! .
As worded, this post MAKES no SENSE,
since it does not define the notion/conception of "options".
Good for re-cycling, only.
Since the post is NONSENSE, do not take seriously that solution, which follows.
It MAKES no SENSE, too.
/\/\/\/\/\/\/
Post - note after reading the post by @greenestamps.
Dear @greenestamps, in opposite to your opinion, I PERFECTLY understand and understood the meaning of the problem.
Nevertheless, I think that in such form no one post may come to the forum and no one post can be accepted.
According to it, my reaction was.
@greenestamps, PLEASE NEVER think about me that I have a lack of brain cells in my head.
I have them quite ENOUGH.
Answer by mccravyedwin(408)  (Show Source):
You can put this solution on YOUR website!
Be sure to post the COMPLETE problem. You did not give us the number of
possible available options that we can select 4 from. Without that number the
problem cannot be worked.
Edwin
Answer by greenestamps(13206)  (Show Source):
You can put this solution on YOUR website!
Two tutors provided responses showing that they did not understand the problem as presented; another tutor provided a response that I think reads something into the problem that is not there.
With 2 models and 8 colors, there are 2*8=16 combinations of model and color.
Then "any combination of 4 options" means there are 4 options available, and you can choose ANY combination of them, including none of them.
Counting the number of combinations of 4 of the options is like finding the number of subsets of a set containing 4 elements; including the empty set (choosing none of the 4 options). The number of subsets of a set with n elements is 2^n, so the number of possible combinations of the 4 options is 2^4=16.
So the total number of possible cars is 2*8*16 = 256.
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