SOLUTION: A jar of coins contains only quarters (25¢) and dimes (10¢). The total amount of money in the jar is $4.40, and there are 23 coins. Let's write a system of equations that can

Algebra ->  Average -> SOLUTION: A jar of coins contains only quarters (25¢) and dimes (10¢). The total amount of money in the jar is $4.40, and there are 23 coins. Let's write a system of equations that can      Log On


   

Question 1173467: A jar of coins contains only quarters (25¢) and dimes (10¢).
The total amount of money in the jar is $4.40, and there are 23 coins.
Let's write a system of equations that can be used to find, the number of dimes, and, the number of quarters, in the jar.
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52792) About Me  (Show Source):
You can put this solution on YOUR website!
.

      q +   d =  23         (counting coins)

    25q + 10d = 440         (counting cents)


q = # of quarters;  d = # of dimes.



Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
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A jar of coins contains only quarters (25¢) and dimes (10¢).
The total amount of money in the jar is $4.40, and there are 23 coins.
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system%28q%2Bd=23%2C25q%2B10d=440%29


OR

system%28q%2Bd=23%2C5q%2B2d=88%29