SOLUTION: A jar of coins contains only quarters (25¢) and dimes (10¢). The total amount of money in the jar is $4.40, and there are 23 coins. Let's write a system of equations that can

Algebra ->  Average -> SOLUTION: A jar of coins contains only quarters (25¢) and dimes (10¢). The total amount of money in the jar is $4.40, and there are 23 coins. Let's write a system of equations that can      Log On


   

Question 1173465: A jar of coins contains only quarters (25¢) and dimes (10¢).
The total amount of money in the jar is $4.40, and there are 23 coins.
Let's write a system of equations that can be used to find the number of dimes, and, the number of quarters, in the jar.
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


d = # of dimes
q = # of quarters

(1) d+q=23 (the total number of coins is 23)
(2) 10d+25q = 440 (the total value of the coins, at 10 cents for each dime and 25 cents for each quarter, is 440 cents)