Question 1173427: Nii went into a supermarket to buy some fruit. There were three packs on special offer:
1) Ten grapes and five strawberries: 700 RWF (save 100 RWF)
2) Ten strawberries and ten apricots: 2000 RWF (save 400 RWF)
3) Thirty grapes: 1000 RWF (save 200RWF)
What would be the full price of one grape, one strawberry and one apricot at normal price (no special offers)?
Enter your answers as the whole number in the blank spaces.
Full price of one grape is________
RWF.
Full price of one strawberry is________
RWF
Full price of one apricot is ________
RWF
Answer by mila nedic(19)   (Show Source):
You can put this solution on YOUR website! Let's say that g=grape, s=strawberry, a=apricot.
1) 10g+5s=700+100 (because we are looking for the original price not the offer
price so we add the discount)
=800 RWF
2) 10s+10a=2000+400 (we add the discount to the price again)
=2400 RWF
3) 30g=1000+200 (discount price added to discount)
=1200 RWD (from here we can use simple algebra to find g)
30g=1200 RWD
g=40 RWD (we divided each side by 30 to isolate g)
Now that we have g=40 RWD we can figure out the rest using g:
1) 10g+5s=700+100
=800
10*40+5s=800 (we input 40 instead of g so now we can find s)
5s=400 (subtract 10*40 or 400 from each side)
s=80 RWF(divide each side by 5 to isolate s and we get the value for s)
We can now use s to find a:
2) 10s+10a=2000+400
=2400 RWF
10*80+10a=2400 (replace s with its value of 80)
10a=1600 (subtract 10*80 or 800 from each side to isolate 10a)
a=160 RWF (divide each side by 10 to isolate a and we get its value)
So now we have the full price of each fruit:
grape=40 RWF
strawberry=80 RWF
apricot=160 RWF
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