SOLUTION: Sketch the graph of each function. Show the coordinates of the vertex, the equation of the axis of symmetry, and the coordinates of two other points on the curve.
y=x2-2x-8
y=-x
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-> SOLUTION: Sketch the graph of each function. Show the coordinates of the vertex, the equation of the axis of symmetry, and the coordinates of two other points on the curve.
y=x2-2x-8
y=-x
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Question 1173297: Sketch the graph of each function. Show the coordinates of the vertex, the equation of the axis of symmetry, and the coordinates of two other points on the curve.
y=x2-2x-8
y=-x2-6x-9
For , the vertex is at the point , and the equation of the axis of symmetry is . For the other two points, choose and calculate , then choose and calculate .
I'm going to assume, given the level of knowledge required to be in a class where this question would be asked that you know how to sketch a graph given a few points.
John
My calculator said it, I believe it, that settles it
From
I > Ø
Hi
Note: the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry.
y=x^2-2x-8 0r Completing the Square
y =x^2-2x +1 -1 -8
y =(x-1)^2-9 V(1, -9) and x = 1 is the Line of Symmetry
the coordinates of two other points on the curve:
P(0, -8) & P(-2, 0)
y=x^2-6x - 9 0r Completing the Square
y =x^2-6x+9 -9 -9
y =(x-3)^2-18 C(3, -18) and x = 3 is the Line of Symmetry
the coordinates of two other points on the curve:
P(2, -17) & P(1, -14)
Wish You the Best in your Studies.
