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f(x)=sqrt(2(3^x))*log(2x+5)
[A] [ B ]
f(x)=sqrt(2(3^x)) *log(2x+5)
A'B = (√2/2) 3^(X/2)log3 *log(2x+5) = (1/√2) 3^(x/2)log3 *log(2x+5)
B'A = (2^(3/2)3^(x/2))/(2x+5)
f' = A'B + B'A + C
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