Question 1173048: (a) What is the average velocity of a car that travels 450 km north in 9.0 hours? show your work answer
(b) A car brakes from 25 m/s to 16 m/s in 2.0 s. What is its acceleration? show your answer
(c) A tangent line drawn on a velocity-time graph has a rise of 19 m/s and a run of 4.0 m/s. How large is the acceleration? show your answer
Answer by ikleyn(52776)   (Show Source):
You can put this solution on YOUR website! .
(a) To find average velocity, divide the traveled distance by the travel time.
The vector is directed North.
(b) To find the acceleration, find the difference of velocities and divide it by the elapsed time.
(c) The "run" in this case is NOT 4.0 m/s. It is 4.0 seconds, INSTEAD.
To find the magnitude of the acceleration, divide the rise of the velocity by the elapsed time.
--------------
It is very crude error, which you made in part (c) saying that "the run is 4 m/s".
So crude, that an expert MOMENTARILY sees that you can not read and understand correctly the kinematic plots.
By the way, the ability "to read" and correctly interpret plots "distance versus time", "velocity versus time",
"acceleration versus time" is one of important skills in Kinematic as a part of Mechanics.
I am telling it to you in order for you know how important it is and avoid such mistakes in the future.
If you have a possibility to exercise more in reading such plots, do not miss it (!)
Good luck (!)
Come again to this forum soon to learn something new (!)
|
|
|
