SOLUTION: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages.

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Question 1173019: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages.
Found 3 solutions by VFBundy, ikleyn, josgarithmetic:
Answer by VFBundy(438) About Me  (Show Source):
You can put this solution on YOUR website!
Daughter's age six years ago = d
Mother's age six years ago = 3d

d + 3d = 36

4d = 36

d = 9

Daughter's age six years ago = d = 9
Mother's age six years ago = 3d = 3(9) = 27

Daughter's age today = 9 + 6 = 15
Mother's age today = 27 + 6 = 33

Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.

After reading your post,  I have a question.

It is about this passage  "The sum of their ages  WAS  36."


To which time moment this statement does relate ?


To the past ?     (6 years ago).

Or to the present ?     (now).

If it relates to the present,  then why you use  "WAS" ?

If to the past,  then it should sound in other way : 

    "The sum of their ages  WAS  36 years then".

Honestly,  I do not need your clarification.


===--->>>   It is  YOU,  "the composer",  who needs it.   <<<---===



Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
w, woman
d, daughter
system%28w-6=3%28d-6%29%2Cw-6%2Bd-6=36%29

w-6=3d-18
w-3d=-12
-w%2B3d=12


w%2Bd=36%2B12
w%2Bd=48


Very Simple System:
system%28-w%2B3d=12%2Cw%2Bd=48%29

ADD: 4d=60
highlight%28d=15%29
-
highlight%28w=33%29