SOLUTION: Jose has some coins in his pocket consisting of dimes, nickels, and pennies. He has two more nickels than dimes, three times more pennies as nickels. How many of each kind of the c
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Question 1173013: Jose has some coins in his pocket consisting of dimes, nickels, and pennies. He has two more nickels than dimes, three times more pennies as nickels. How many of each kind of the coins does he have if the total value is 52 cents. Answer by VFBundy(438) (Show Source):
You can put this solution on YOUR website! Dimes = d
Nickels = d + 2
Pennies = 3(d + 2) = 3d + 6
0.10d + 0.05(d + 2) + 0.01(3d + 6) = 0.52
0.10d + 0.05d + 0.10 + 0.03d + 0.06 = 0.52
0.18d + 0.16 = 0.52
0.18d = 0.36
d = 2
Dimes = d = 2
Nickels = d + 2 = 2 + 2 = 4
Pennies = 3(d + 2) = 3d + 6 = 3(2) + 6 = 6 + 6 = 12
