Question 1172843: A rectangle has perimeter 128 cm and its length is 1 cm more than twice its width.
Find the dimensions of a rectangle given that its perimeter is 128 cm and its length is 1 cm more than twice its width.
Set up your solution using the variables L for the length, W for the width, and P for the perimeter.
Part a: Using the definition of perimeter, write an equation for P in terms of L and W.
Part b: Using the relationship given in the problem statement, write an equation for L in terms of W.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! P=2L+2w; worth drawing this.
(1/2)P=L+W (not commonly used but simpler in some ways.)
64=L+W, but L=2W+1
so 64=2W+1+W
3W=63
W=21 cm
L=43cm
perimeter is 2(21)+2(43) or 128 cm.
|
|
|
