SOLUTION: A recent estimate suggested that, of all individuals and couples reporting income in excess of $200,000, 6.5% either paid no federal tax or paid tax at an ef- fective rate of le

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Question 1172798: A recent estimate suggested that, of all individuals
and couples reporting income in excess of $200,000,
6.5% either paid no federal tax or paid tax at an ef-
fective rate of less than 15%. A random sample of 100
of those reporting income in excess of $200,000 was
taken. What is the probability that more than 2 of the
sample members either paid no federal tax or paid tax
at an effective rate of less than 15%?

Found 3 solutions by ewatrrr, MathTherapy, math_tutor2020:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Binomial , Cumulative Distribution
p(desired outcome) = .065, n = 100
P(x >2) = 1 - P(x ≤ 2) = 1 - binomcdf(100, .065, 2) = 1-.0384 = .9616
Recommend using stattrek.com Binomial calculator to check YOUR work.
Wish You the Best in your Studies.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
A recent estimate suggested that, of all individuals and couples reporting income in excess of $200,000, 6.5% either paid no federal tax or paid tax at an effective rate of less than 15%. A random sample of 100 of those reporting income in excess of $200,000 was taken. What is the probability that more than 2 of the sample members either paid no federal tax or paid tax at an effective rate of less than 15%?
highlight_green%28matrix%281%2C3%2C+%220.96157585%2C%22%2C+or%2C+%2296.16%25%22%29%29 


Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

The tutor @ewatrrr has the correct answer because P(X > 2) = 0.9616 approximately

In contrast, @MathTherapy computed P%28X%3E=2%29 to get roughly 0.9904; but the question isn't asking "2 or more". Instead the question is asking for the probability of getting "more than 2".

Edit: Disregard this because @MathTherapy has fixed their solution.