Question 1172795: For 3 ensurance companies, the chances that a client closes an ensurance deal are 15%, 16% , 17%. Three clients enter simultaniously, one in each of the 3 companies. What's the probability of?
1. 2 clients close an ensurance deal?
2. At least 2 clients close an ensurance deal?
Answer by ikleyn(52835)   (Show Source):
You can put this solution on YOUR website! .
For 3  insurance companies, the chances that a client closes an insurance deal are 15%, 16% , 17%. T
Three clients enter  simultaneously, one in each of the 3 companies. What's the probability of?
1. 2 clients close an insurance deal?
2. At least 2 clients close an insurance deal?
~~~~~~~~~~~~~~~~~
(1) P = P(1st yes, 2nd yes, 3rd no) + P(1st yes, 2nd no, 3rd yes) + P(1st no, 2nd yes, 3rd yes) =
= 0.15 * 0.16* (1-0.17) + 0.15 * (1-0.16) * 0.17 + (1-0.15) * 0.16 * 0.17 = 0.06446.
(2) P = P(1st yes, 2nd yes, 3rd no) + P(1st yes, 2nd no, 3rd yes) + P(1st no, 2nd yes, 3rd yes) + P(all 3 yes) =
= 0.15 * 0.16* (1-0.17) + 0.15 * (1-0.16) * 0.17 + (1-0.15) * 0.16 * 0.17 + 0.15*0.16*0.17 = 0.06854.
Solved.
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