SOLUTION: Factor completely. 15x^2 – 21x + 6

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Question 117273: Factor completely. 15x^2 – 21x + 6
Found 2 solutions by bucky, jim_thompson5910:
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given to factor:
.
15x%5E2-21x%2B2
.
Notice first that each of the numbers in the three terms is divisible by 3, so the factor 3
can be removed. This results in:
.
3%2A%285x%5E2+-+7x+%2B+2%29
.
So now let's concentrate on factoring the terms inside the parentheses. Note that 5x%5E2 can
only be factored into 5x%2Ax. Therefore, if the trinomial in the parentheses can be
factored, the factors will be of the form:
.
(5x ______)*(x _____)
.
Next notice that the last term in the trinomial is +2. It's factors can only be +2 and +1 or
-2 and -1 because they must multiply together to give +2. Since the middle term of the
trinomial is -7 we have to have minuses in the factors of the trinomial. So we assume that
the factors of +2 that we will use are -2 and -1. This leaves two possibilities:
.
(5x - 1)*(x - 2)
.
or
.
(5x - 2)*(x - 1)
.
When you multiply out the (5x - 1)*(x - 2) you get 5x%5E2+-10x+-+x+%2B+2 which reduces to
5x%5E2+-+11x+%2B+2 so this combination does not work.
.
When you multiply out the (5x - 2)*(x - 1) you get 5x%5E2+-+5x+-+2x+%2B+2 and this does reduce
to 5x%5E2+-7x+%2B2, just as we need.
.
So now we can say that the given:
.
15x%5E2+-+21x%2B2
.
factors to:
.
3%2A%285x+-+2%29%2A%28x+-+1%29
.
None of the expressions inside the parentheses can be factored, so this is the final answer.
.
Hope this helps to see how the given trinomial can be factored using a "logical" analysis and
a little bit of trial.
.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at 15x%5E2-21x%2B6 we can see that the first term is 15x%5E2 and the last term is 6 where the coefficients are 15 and 6 respectively.

Now multiply the first coefficient 15 and the last coefficient 6 to get 90. Now what two numbers multiply to 90 and add to the middle coefficient -21? Let's list all of the factors of 90:



Factors of 90:
1,2,3,5,6,9,10,15,18,30,45,90

-1,-2,-3,-5,-6,-9,-10,-15,-18,-30,-45,-90 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 90
1*90
2*45
3*30
5*18
6*15
9*10
(-1)*(-90)
(-2)*(-45)
(-3)*(-30)
(-5)*(-18)
(-6)*(-15)
(-9)*(-10)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to -21? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -21

First NumberSecond NumberSum
1901+90=91
2452+45=47
3303+30=33
5185+18=23
6156+15=21
9109+10=19
-1-90-1+(-90)=-91
-2-45-2+(-45)=-47
-3-30-3+(-30)=-33
-5-18-5+(-18)=-23
-6-15-6+(-15)=-21
-9-10-9+(-10)=-19



From this list we can see that -6 and -15 add up to -21 and multiply to 90


Now looking at the expression 15x%5E2-21x%2B6, replace -21x with -6x%2B-15x (notice -6x%2B-15x adds up to -21x. So it is equivalent to -21x)

15x%5E2%2Bhighlight%28-6x%2B-15x%29%2B6


Now let's factor 15x%5E2-6x-15x%2B6 by grouping:


%2815x%5E2-6x%29%2B%28-15x%2B6%29 Group like terms


3x%285x-2%29-3%285x-2%29 Factor out the GCF of 3x out of the first group. Factor out the GCF of -3 out of the second group


%283x-3%29%285x-2%29 Since we have a common term of 5x-2, we can combine like terms

So 15x%5E2-6x-15x%2B6 factors to %283x-3%29%285x-2%29


So this also means that 15x%5E2-21x%2B6 factors to %283x-3%29%285x-2%29 (since 15x%5E2-21x%2B6 is equivalent to 15x%5E2-6x-15x%2B6)

-------------------------------
Answer:

So 15x%5E2-21x%2B6 factors to %283x-3%29%285x-2%29