Question 1172721: In an urn, 4/7 of the chips are red and the rest are blue. If the number of red chips is reduced by half and the number of blue chips is doubled, what is now the fraction of red chips in the urn?
Answer by Solver92311(821)   (Show Source):
You can put this solution on YOUR website!
If  are red, and the rest are blue, then  are blue. Assuming that the total number of chips, both red and blue, is an integer, then the total number of chips must be an integer multiple of 7, which is to say that the total number of chips is  such that  is an integer. Therefore the original number of red chips is  and the number of blue chips is  .
Half of the red chips are  , and double the blue chips is  . Now there are a total of  chips in the urn.  of the chips are red, and therefore  of the chips are blue.
John
My calculator said it, I believe it, that settles it
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