SOLUTION: How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosin
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Question 1172701: How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines) Found 2 solutions by ankor@dixie-net.com, ikleyn:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! How would I go about finding the area of a triangle with 2 sides and 1 angle given? Eg: one side is 120, the other 200 with an angle of 41 between them. (without using law of cosines)
:
We can find the height. A right triangle is formed, using sin(41), hypotenuse = 120 and side opposite is h,
so we have: sin(41) =
h = 78.7271
A = b*h, where b=200 and h=78.73
A = *200*78.7271
A = 7872.7 sq/units
If two sides of a triangle are given as " a" and " b" with the angle between them,
then there is a STANDARD FORMULA for the area of the triangle
area = .
M E M O R I Z E it and use it every time in this situation.
There is NO NEED to derive it every time anew - it is a STANDARD FORMULA for everyday use, which people know and use for thousands years.
