SOLUTION: VARIATION: The distance (d) from the center of the seesaw varies inversely as the weight (w) of a person. JB who weighs 50 kg sits 3 feet from the fulcrum. How far from the fulc

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: VARIATION: The distance (d) from the center of the seesaw varies inversely as the weight (w) of a person. JB who weighs 50 kg sits 3 feet from the fulcrum. How far from the fulc      Log On


   

Question 1172683: VARIATION:
The distance (d) from the center of the seesaw varies inversely as the weight (w) of a person. JB who weighs 50 kg sits 3 feet from the fulcrum. How far from the fulcrum must JP sit in order to balance with JB if he weighs 35 kg?
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.

The governing equation for seesaw to be in equilibrium is


    50*3 = 35*x.


Find x from this equation.

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Formulation of this simple problem is artificially made so unjustly complicated
using these mysterious names JB and JP,
that it is just the time to call for the urgent medical assistance.