SOLUTION: If you adhere to the requirements of the birthday problem (no twins, no leap year, an equal chance of any day of the year being a birthday), how many people do you need in a group

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Question 1172638: If you adhere to the requirements of the birthday problem (no twins, no leap year, an equal chance of any day of the year being a birthday), how many people do you need in a group so that there is a greater-than-average chance that at least two of them share the same birthday?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi  

There's many references on line for same birthday probabilities

Wish You the Best in your Studies.

how many people do you need in a group so that there is 

a greater-than-average chance that at least two of them 

share the same birthday?  23

 .