SOLUTION: The half-life of Zn-71 is 2.45 minutes. At t=0, there were y⁰ grams of Zn-71, but only 1/256 of this amount remains after some time. How much time(t) has passed?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The half-life of Zn-71 is 2.45 minutes. At t=0, there were y⁰ grams of Zn-71, but only 1/256 of this amount remains after some time. How much time(t) has passed?      Log On


   



Question 1172591: The half-life of Zn-71 is 2.45 minutes. At t=0, there were y⁰ grams of Zn-71, but only 1/256 of this amount remains after some time. How much time(t) has passed?
Answer by ikleyn(52878) About Me  (Show Source):
You can put this solution on YOUR website!
.

1%2F256 = 1%2F2%5E8.


So we conclude that 8 half-life periods passed from t= 0.


8 half-lives is 8*2.45 minutes = 19.6 minutes = 19 minutes and 36 seconds.    ANSWER

Solved.

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To learn more on the subject,  look into the lesson
    - Radioactive decay problems
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.