SOLUTION: A student throws a ball vertically up with a speed of 33 m/s.
a.) How high will the ball rise before it goes down?
b.) How long will the ball stay in air before landing back to h
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-> SOLUTION: A student throws a ball vertically up with a speed of 33 m/s.
a.) How high will the ball rise before it goes down?
b.) How long will the ball stay in air before landing back to h
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Question 1172457: A student throws a ball vertically up with a speed of 33 m/s.
a.) How high will the ball rise before it goes down?
b.) How long will the ball stay in air before landing back to his hand?
You can put this solution on YOUR website! A student throws a ball vertically up with a speed of 33 m/s.
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Using g = 9.8 m/sec/sec for gravity:
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a.) How high will the ball rise before it goes down?
That's the max height.
It's the vertex of the parabola of h(t) = -gt^2/2 + 33t ---- t in seconds
h(t) = -4.9t^2 + 33t
Vertex is t = -b/2a = -33/-9.8
Max height = h(33/9.8) meters
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b.) How long will the ball stay in air before landing back to his hand?
Time ascending = time descending
= 2*(33/9.8)
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If you meant to use 10 m/sec/sec for gravity to make it easier, you have to specify that.
