SOLUTION: A sequence Tn is defined by T1 = T2 = 1 and T(n+2) = T(n+1) + Tn Tn = {{{(a^n - b^n)/ sqrt( 5 )}}}, where a,b (a>b) are the roots of {{{x^2 - x -1=0}}}. Assume the ratio {{{T

Algebra ->  Sequences-and-series -> SOLUTION: A sequence Tn is defined by T1 = T2 = 1 and T(n+2) = T(n+1) + Tn Tn = {{{(a^n - b^n)/ sqrt( 5 )}}}, where a,b (a>b) are the roots of {{{x^2 - x -1=0}}}. Assume the ratio {{{T      Log On


   



Question 1172425: A sequence Tn is defined by T1 = T2 = 1 and T(n+2) = T(n+1) + Tn
Tn = %28a%5En+-+b%5En%29%2F+sqrt%28+5+%29, where a,b (a>b) are the roots of x%5E2+-+x+-1=0.
Assume the ratio T%28n%2B1%29%2FTn approaches a limit as n approaches infinity. Show that T%28n%2B1%29%2FTn approaches %281%2B+sqrt%28+5+%29%29%2F2

Answer by ikleyn(52769) About Me  (Show Source):
You can put this solution on YOUR website!
.

See the link

https://www.nctm.org/tmf/library/drmath/view/52696.html

and find the solution there.