SOLUTION: Sam is working on some polynomial factorizations in the form of x^2 + px + q , where p and q are nonzero integers. His work is as follows: x^2 −2x−3=(x−3)(x+1) x^2 +5x+6=(

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Sam is working on some polynomial factorizations in the form of x^2 + px + q , where p and q are nonzero integers. His work is as follows: x^2 −2x−3=(x−3)(x+1) x^2 +5x+6=(      Log On


   



Question 1172364: Sam is working on some polynomial factorizations in the form of x^2 + px + q , where p and q are nonzero integers. His work is as follows:
x^2 −2x−3=(x−3)(x+1)
x^2 +5x+6=(x+2)(x+3)
x^2 −7x+10=(x−2)(x−5)
x^2 +6x+8=(x+2)(x+4)
x^2 −8x+12=(x−2)(x−6)
x^2 +9x+18=(x+3)(x+6)
He concludes that if p and q are coprime, then the factors a and b are also coprime. If p and q are not coprime, then the factors a and b are not coprime, either.
Is his conclusion correct? Explain please.

Answer by ikleyn(52809) About Me  (Show Source):
You can put this solution on YOUR website!
.

Hello, from your post,  it is  UNCLEAR  to me what you call as  "the factors a and b" ?

They are not defined anywhere in your post,  making it non-sensical.

If you mean  "a"  and  "b"  as linear binomials,  then they  ALWAYS  are coprime as polynomials,  until they coincide.