SOLUTION: In a triangle ABC , BC=24 and angle A=60 degree . D ,M are the points on side AC and E , N are the points on AB such that DN and EM are the perpendicular bisectors of AC and AB

Algebra ->  Triangles -> SOLUTION: In a triangle ABC , BC=24 and angle A=60 degree . D ,M are the points on side AC and E , N are the points on AB such that DN and EM are the perpendicular bisectors of AC and AB       Log On


   



Question 1172341: In a triangle ABC , BC=24 and angle A=60 degree . D ,M are the points on side
AC and E , N are the points on AB such that DN and EM are the perpendicular
bisectors of AC and AB respectively . If L be the mid-point of MN , then the
perimeter of triangle ELD is ...??

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
In a triangle ABC , BC=24 and angle A=60 degree . D ,M are the points on side AC and E , N are the points on AB such that DN and EM are the perpendicular bisectors of AC and AB respectively .

The triangle above is an equilateral triangle with points N and B coinciding,
as well as M and C.  The problem does not state that it must be this way, but
considering it to be this way certainly fits the solution.  So this IS a
solution.

If L be the mid-point of MN , then the perimeter of triangle ELD is ...??
We will draw triangle ELD as stated (in red):



Red triangle ELD is congruent to triangle EAD, so its perimeter is 12+12+12=36.

Edwin