SOLUTION: Obtain the equation of the straight line passing through the point (4, 5) and
(i) parallel to
(ii) perpendicular to 3x-2y+5=0
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-> SOLUTION: Obtain the equation of the straight line passing through the point (4, 5) and
(i) parallel to
(ii) perpendicular to 3x-2y+5=0
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Question 1172316: Obtain the equation of the straight line passing through the point (4, 5) and
(i) parallel to
(ii) perpendicular to 3x-2y+5=0 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 3x-2y+5=0 may be rewritten as 2y=3x+5 or y=(3/2)x+(5/2). The slope is 3/2, so any line parallel to this one has slope (3/2) and any line perpendicular to it has slope -2/3, the negative reciprocal.
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point slope formula, y-y1=m(x-x1) m slope and (x1, y1) point
y-5=(3/2)(x-4)
y=(3/2)x-1. answer to i
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y-5=(-2/3)(x-4)
y=(-2/3)x+25/3, answer to ii
