SOLUTION: If n = (p1)^α1 .(p2)^α2 .(p3)^α3 .(p4)^α4 .....(pr)^αr where p1 , p2 , p3 , ...., pr are distinct prime numbers then following result hold:
d(n) = summation of (αi + 1). [
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-> SOLUTION: If n = (p1)^α1 .(p2)^α2 .(p3)^α3 .(p4)^α4 .....(pr)^αr where p1 , p2 , p3 , ...., pr are distinct prime numbers then following result hold:
d(n) = summation of (αi + 1). [
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Question 1172315: If n = (p1)^α1 .(p2)^α2 .(p3)^α3 .(p4)^α4 .....(pr)^αr where p1 , p2 , p3 , ...., pr are distinct prime numbers then following result hold:
d(n) = summation of (αi + 1). [Here ^ means power] Answer by ikleyn(52787) (Show Source):
