Question 1172239: Solve the problems in one variable.
A company decided to invest P100, 000 which was partly invested on a bank account paying 8% per annum and the remainder was invested in stocks paying 11% per annum. If the total yearly interest from the two investments is P10, 100, how much was invested in each? 3 points.
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
x = amount invested at 8%
100000-x = amount invested at 11%
The total interest is 10100:
Solve using basic algebra....
Doing the above is a good exercise in solving problems using formal algebra.
For a quick and easy way to answer a "mixture" problem like this, you can do this:
(1) The 100,000 all invested at 8% would earn 8000 interest; all at 11% would earn 11,000 interest; the actual interest is 10,100.
(2) View the three numbers on a number line and use simple calculations to determine that 10,100 is 7/10 of the way from 8000 to 11,000.
(3) That means 7/10 of the total 100,000 was invested at the higher rate.
ANSWER: 7/10 of the total 100,000, or 70,000 was invested at 11%; the other 30,000 at 8%.
CHECK: .11(70,000)+.08(30,000) = 7700+2400 = 10,100
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